Posted: Fri Feb 29, 2008 1:36 pm
Some of you guys take this hobby to a whole new level....I'm jealous
There ARE fast response thermocouples out there, but they're FRAGILE and as such highly unreliable. In other words, I agree with your conclusion that thermocouples are ill-suited.jimmy101 wrote:Any thoughts on how you are going to do temperature? I've considered trying a thermocouple but the heat capacity and response times seem to be totally unuseable for combustion gases in a closed chamber or gun.
Damn, that makes a heck of a lot of sense. I was just figuring that the factor of 2 was to account for the flame front converting to turbulent at some point. The model doesn't take that into account so the "2x factor" in initial flame speed was just a very crude fix. It overestimates the initial flame speed (but that is probably OK since anything that happens before the spud starts to move to relatively less important) but gives a better estimate of what is happening at higher combustion fractions when the spud is moving and the flame front is more likely to be turbulent.D_Hall wrote:On a related note, I wanted to respond to something you said in another thread but I've not been able to find it. Somewhere you mentioned that you have to use roughly double-speed flame propogation as a starting point to get your mathematical model to work. IE, 0.8ish as opposed to 0.43 m/s.
I think I've an idea as to why.
As I understand your webpage, the 0.43 number you cite is for propogation through quiescent air. In real world terms, this would be the flame propogation rate of an open pipe lit at the open end.
But that's not what we do. We light elsewhere. For the purpose of simplicity, let's say that we lit that open pipe at the closed end.
For a brief instant everything is sitting still and the flame rate would indeed be in the range of 0.43. But here's the catch... The hot gases are expanding. They push the cold gases out in front. The flow is laminar, but it is a flow. It is NOT quiescent. So.... If we attempt to view it as quiescent air we must move our reference frame at the same rate as the flow near the flame front. How fast will that be in the immediate aftermath of igniton? It'll be very nearly the same as the flame propogation rate as the hot gases have a density that is a fraction of the cold gases. Result? Flame propogation rate as measured by a stationary observer will be on the order of 0.8 m/s.
Of course, the flow will quickly become turbulent and all hell will break loose, but at least at the moment I'm thinking that the difference between 0.43 and 0.8 is literally nothing more than the difference of which end we light the tube from.