SpudFiles

I was wondering what kind of force would be placed on a sear holding a 1 inch piston back from say 80 psi? I know I should know how to figure this out but I am drawing a blank here. So any help would be appreciated.

surface area of piston x pressure = (0.5" x 0.5" x 22/7) x 80 = 62.84 lb

Thanks a lot, regular cold rolled steel should have no problem with that riight?

it should be ok, if in doubt you could always hang 62.84lb of weights from it to simulate the strain caused by the pressure.

I think I should be good, Im planning on making something similar to the HEAR valve.

You can always anneal a section of a metal file and shape the sear from it and then re-temper it. Very easy to do and you don't have to get it perfect. It will wear better as well.

shouldnt the equation for the force be

(Pi X Diamter of the piston) X pressure of the cylinder?

that would be 3.14in2 X 100 PSI, wich would mean : approximately 314 pounds of force.

314 is alot of force, but ive seen pneumatic cylinders with a 1 inch bore that have bent 1/4 inch steel.......

VH_man wrote:shouldnt the equation for the force be

(Pi X Diamter of the piston) X pressure of the cylinder?

No.

Force = area of piston x pressure acting on piston = pi x radius squared x pressure

ah. that makes sense now......

that helps me alot... wow now i have to re-examine the actual strentgh of my robotics project.

pneumatic rams are powerufl, but apparently ive overestimated their strenght.... dang nabit......