piston travel

[no-limit]

How far back should the piston go? Should it clear the opening to the chamber all the way?

[daxspudder]

Just 1/4 of the diameter of the chamber is all that is needed to be efficient.

[no-limit]

Getting tired here, so does that mean if I have a 2" T it should go back 1/2". Doesn't seem like enough, that's why I'm trying to clairfy it.

[watto]

1/4 of the barrel diameter is only for coaxials, if your using a tee make it a bit more, Ive got a 2" tee with a golf ball barrel and mine moves back 1.5cm

[clide]

1/4 of the seat diameter is all that is needed for a coaxial. For a tee valve, especially one with the seat close to the tee diameter, the 1/4 guideline may not apply. I would suggest 1/2 of the seat diameter if the seat is close to the diameter of the piston housing.

Edit: bah, watto beat me to it

[no-limit]

1/4 of the barrel dia. is what is used for pilot volume, so it makes sense now for that to be the amount of travel for the piston. Doesn't seem to open enough.

[starman]

1/4 of the barrel dia. is what is used for pilot volume, so it makes sense now for that to be the amount of travel for the piston. Doesn't seem to open enough.

But it is...do the area math and you'll see.

[no-limit]

If only I could!

[SpudFarm]

why don't you just make it 1/3 of the diameter on the barrel and stop thinking?

[no-limit]

Because 1+1+11. Or how about 1/2.

[no-limit]

Can someone explain the "area math" to me so I can try and do it.

[SpudFarm]

to put the theorie as i use it in aspect:
air comes rushing from 4 different main angles wich make one whole.

when i think of it GGDT has no "piston travel"

[no-limit]

Does that mean I shouldn't have any travel, lol.

[clide]

GGDT assumes the piston is fully open at 1/4 of the seat.

The math is fairly simple.
Your seat is (usually) a circle so its cross-sectional area is pi*r²

As the piston moves back imagine the area created where the air can move from the chamber to the barrel. You should be imagining a cylinder extending back from the pipe that the piston seats against. The surface area of the outside of a cylinder is 2*pi*r*h
The r would be the same in both cases and the h would be the travel of the piston.

To get the point where the flow through that cylinder equals the flow through the circular cross section you would simply set them equal to each other.
pi*r² = 2*pi*r*h

Then it is just a matter of solving for h to get
h = r/2

Since we deal with diameter much more often than radius just use r = d/2 to get:
h = d/4

[no-limit]

Thanks, I have a friend who can show me how to use this formula, I suck at math.